Question:
An object with a mass of 5.00 kg slides on an ideal frictionless surface. The object is pulled with a constant horizontal force of 10.0 N as shown below. What is the resulting acceleration?
Answer:
We can most easily get our results by again working in components (x and y). What we need to do is to write down all force components in x- and in y-direction separately.
y:
$\sum$ Fy = N - mg = 0
=> N = m g
x:
$\sum$ Fx = F = m ax = m a
=> a = F/m = (10.0 N)/(5.00 kg)
=> a = 2.00 m/s2Thus what we find is that the acceleration is 2.00 m/s2 in x-direction.
There are two important lessons to be learned here:
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